Fórmulas FQ Netz

Prévia do material em texto

R = 0, 082 atmLK−1mol−1 = 8, 314 JK−1mol−1 = 1, 987 calK−1mol−1 kB = 1, 38×10
−23 JK−1
NA = 6, 02× 10
23mol−1 g = 9, 81m s−2 h = 6, 62× 10−34J s F = 96500Cmol−1
1 atm = 101325Pa = 760mmHg 1 bar = 100000Pa t(oC) = T (K)− 273, 15
1 atmL = 101, 325Pam3 = 101, 325 J = 24, 23 cal 1 cal = 4, 184 J 1 J = 1× 107erg
1 Å = 1× 10−10m 1N = 1× 105dina 1N = 1 kgm s−2 1 J = 1VC
z =
V
Videal
z = z(P, T ) PV = znRT
[
PvdW + a
( n
V
)2
]
(V − nb) = nRT
π =
P
PC
θ =
T
TC
φ =
V
VC
z =
PCVC
RTC
πφ
θ
= zC
πφ
θ
αP =
1
V
(
∂V
∂T
)
P
κT = −
1
V
(
∂V
∂P
)
T
γV =
(
∂P
∂T
)
V
dU = d−q + d−w d−wexp = −PextdV d
−qX = CXdT dS ≥
d−q
T
∆Suniv = ∆Ssis+∆SME H = U +PV A = U −TS G = H−TS
(
∂H
∂T
)
P
= CP
(
∂U
∂T
)
V
= CV γ =
CP
CV
C idP = C
id
V +R = L
R
2
+R
Adiab.revers.
(
V2
V1
)γ−1
=
T1
T2
(
P2
P1
)
γ−1
γ
=
T2
T1
P1V
γ
1 = P2V
γ
2
Z(X, Y ) ↔ dZ =
(
∂Z
∂X
)
dX+
(
∂Z
∂Y
)
dY U(S, V ) H(S, P ) A(T, V ) G(T, P )
Z = Z(T, P, λ) ⇒ dZ =
(
∂Z
∂T
)
P,λ
dT +
(
∂Z
∂P
)
T,λ
dP +
(
∂Z
∂λ
)
P,T
dλ
dni
νi
= dλ ⇒ ∆ZReação =
(
∂Z
∂λ
)
P,T
=
∑
i
νiZ̃i
∂
(
G
T
)
∂T
= −
H
T 2
(
∂U
∂V
)
T
= T 2
∂
(
P
T
)
∂T
dU = TdS − PdV +
∑
k
µkdnk
µk =
(
∂U
∂nk
)
S,V,nj
=
(
∂H
∂nk
)
S,P,nj
=
(
∂G
∂nk
)
P,T,nj
=
(
∂A
∂nk
)
V,T,nj
∑
k
nkdµk,P,T = 0
L = C + 2− φ µk = µ
0
k +RT ln ak dµ = −SdT + V dP
dP
dT
=
∆S
∆V
ln
P2
P1
= −
∆H
R
(
1
T2
−
1
T1
)
lnP = 10.6
(
1−
Teb
T
)
∆rG =
(
∂G
∂λ
)
T,P
=
∑
i
νiµi ∆rG = ∆rG
O +RT lnQ K = e−
∆G0
RT
ln
K2
K1
= −
∆H
0
R
(
1
T2
−
1
T1
)
KP = KC (RT )
∆ν = KxP
∆ν = Kn
(
P
ntot
)∆ν