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Step of 4 2.092P The op-amp is in inverting configuration. Therefore, the transfer function is, R, Here R, = -R2 and is a series combination of and C. = sC = sC Substitute for R, and sC for in the equation. R, = sC = K = Here, K = = 1 Step of 4 The 3 dB frequency can also be represented in terms of as, = High frequency input resistance is 1k. Here, = + sC At high frequencies term vanishes. Therefore, sC = kΩ The Dc gain is 40 dB. 20log K = 40 dB 100 Step of 4 Find the value of from the expression of K K Substitute K = 100, and = KR, = 100(1 kΩ) = 100 kΩ Find the other component values. 1 1 = = Step 4 of 4 The magnitude of the transfer function must be equal to 1. Therefore, K 1 = = f 1 f = Substitute K = = 2 1 f = Hz = 20 Hz Hence magnitude of transfer function reduce to unity at frequency of