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11.15 OH H OH H a) b) c) CH₂CH₃ + enantiomer + enantiomer OH 11.16 The right alcohol is the major + product because the boron prefers to bond to the less OH hindered carbon of the alkene. Major 11.17 OH 1) H₂O a) 2) NaBH4, NaOH 1) BH₃, THF b) OH 2) H₂O₂, NaOH OH H₂O c) 11.18 a) b) Ph H 174