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Step 36 3.008P The current flow due to both electron and hole I JA (1) The current density is, J=σ E σ Substitute C for which represents charge of an electron 1200 for Pn which represents mobility of electron 500 for which represents mobility of hole for n which represents free electron density for p which represents hole density = 0.8 mho/cm Step 36 The electric field V Substitute for voltage Vand 10 for length E 10 0.1 J E Substitute 0. for E and 0.8 mho/cm for σ V/µm(0.8 mho/m) V.mho = 0.08 = A/m2 Step 36 Calculate the area of cross Determine the current I Substitute 106 A/m2 for Jand 20 for A Therefore, the current flow due to both electrons and holes is Step 36 Step 5 of 36 Step 6 of 36 Step 7 of 36 Step 36 Step 9 of 36 Step 10 of 36 Step 36 Step 36 Step 36 Step 36 Step 36 Step 36 Step 36 Step 36 Step 36 Step 20 36 Step 36 Step 22 36 Step 36 Step 36 Step 25 36 Step 26 36 Step 36 Step 28 36 Step 36 Step 36 Step 36 Step 32 36 Step 36 Step 36 Step 36 Step 36