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Step of 5 1.032P Write the expression for Fourier series representation of a square wave signal. (1) Here, Vis the amplitude of the square wave and is the angular frequency Here, time period of square wave The ith is odd) harmonic of fundamental frequency is, =98 kHz And (i+2)* harmonic frequency is, =126kHz Subtract harmonic frequency from (i+2)* harmonic frequency. = 28 kHz Calculate the fundamental frequency. 28 kHz Therefore, the fundamental frequency, is Step of 5 Write the expression for frequency. 98 kHz Substitute 14 kHz for in the equation. i 98 kHz 14 kHz =7 The amplitude of 7th harmonic is 63mV Let amplitude of fundamental be Calculate the amplitude of harmonic. 63 mV = 7 441 mV Therefore, the amplitude of fundamental frequency component, A. is Step of 5 Write the expression for the rms voltage of fundamental term. Substitute 441 mV for A. in the equation. = 441 mV = = 311.8 mV Therefore, the rms voltage, of fundamental term is 311.8 mV 311.8 Step of 5 Calculate the peak-to-peak amplitude of square wave signal. 4V 441 mV V = mV)π 2 Therefore, the peak-to-peak amplitude of square wave signal, V is 692.7 mV Step of 5 Write the expression for the time period of the square-wave signal. T Substitute 14 kHz for in the equation. T 1 14 kHz 71.43 Therefore, the time period, T of the originating square-wave signal is