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44 8.15 Our reaction scheme is medium R fast A medium S 4 4 slow T rate Combining gives = 1 + = + k13 0.21 4.2 = 0.2 A 0.2 0.004 S T thus 0.4 0.004 A S T or K123 = 100 K123 K4 Since S is desired use plug flow. Then an extension of Eq.49 gives = CAO 0.4 -0.4) 0.004 = 0.955 or = 0.955 CAO 8.17 Since this is a course on chemical reactors let US make analogy of this process to a chemical process. Let A = garbage still to be collected = 1440 tons R garbage in the bin S = garbage placed in the Then lan garbage A dA dt = k, at t=0 dAo dr 6 = dA/dt A = 6 = 240 Then 1440 A n, R S = 240 k₂= = ton/min with dA A and dR = (i) dt dt

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