1 (1354)

Prévia do material em texto

Step 1 of 13 13.033P Figure textbook The current passing through The ression emitter voltage (1) The expression fo base emitter voltage (2) Step 2 of 13 Divide with equation The base emitter voltage transistor an transistor since he base emitter junctions o the transistor parallel Step 3 of 13 Substitute Substitute for A for 3 =0.1825 mA Step 4 of 13 Write expression voltage Substitute 25 mV VT for 50+1 50 0.75x10" (0.75) Thus, the value and Step 5 of 13 Determine 50 50+1 25x10 Thus the value Step 6 of 13 Determine conductance 50 50+1 Thus the value 8m Step 7 of 13 50 50+1 50 51 =0.98 The between base emitter 8. Step 8 of 13 for transistor A 0.98 Thus he value transisto Step 9 of 13 Calculate th value of 0.98 Thus he value Step 10 of 13 The input resistance between base standard npn transistor is B Determine Thus the value for transistor Step 11 of 13 Determine for transistor B 50 Thus Step 12 of 13 ression the output resistance transistor Determine 50 50+1 Thus output Step 13 of 13 Determine for transistor B a 50 50 50+1