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Step 1 of 3 13.066P Refer to Figure 12.13 in the textbook for the 741 op-amp circuit. In the 741 sinking-current limit involving R, Qu and the current in the transistor is equal to the maximum current available from the output stage, that is, the current in the transistor The reduced current limit is 10 mA The maximum current available from the output stage, that is, the current in the transistor is The base to emitter voltage of the transistors is, =0.534 V Thus the current through the resistor is, = Step 2 of 3 The collector current of the transistor is, The reverse saturation current of transistor is, A The base to emitter voltage of the transistor is, =0.545 V Step 3 of 3 Now, the current through the resistor R, is, Thus, the current through the resistor R, for maximum current at the input stage is, 20.2 mA If this current is reduced to 10 then the simple change would be to double the resistance value. mA ≈ That is, =2(27) Ω Therefore, make the resistance double to reduce the current limit to 10 mA.