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Step of 7 6.019P Write the relation between saturation currents and = area of EBJ junction area of CBJ junction npn transistor has a CBJ with an area 100 times that of the EBJ. Iₛ = area of EBJ junction area of CBJ junction = area of EBJ junction 100 (area of EBJ junction) Step of 7 Saturation current emitter base junction is, = Determine the saturation current for collector base junction. 100/s = A) Step of 7 Both EBJ and CBJ junction are forward biased and hence npn transistor is operated in saturation mode. Current flowing between collector and emitter junction is, Current flowing between base and collector junction is, Given that Conducting current for each junction is 1 mA for npn transistor hence (1) = A (2) Step of 7 Thermal voltage is 25 mV approximately at room temperature. From equation (1), Apply natural log on both sides, Therefore, the voltage drop across EBJ for npn transistor is 0.69 V Step of 7 From equation (2), Apply natural log on both sides, Therefore, the voltage drop across CBJ for npn transistor is 0.575 V Step of 7 Forward bias voltage applied across EBJ is V Current flowing between emitter and base is = = = 0.48 Therefore, the current flowing between emitter and base junction is Step of 7 Forward bias voltage applied across CBJ is V Current flowing between base and collector junction isc is = = = 48.5 Therefore, the current flowing between base and collector junction isc is