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Step of 5 4.026E Refer to Figure E4.26 in the textbook. Case (1): for The diode is in forward bias and the diode is in reverse bias. An ideal diode acts as short circuit if forward biased and acts as an open circuit if reverse biased. Draw the equivalent circuit. + I I + - v, + - Figure 1 Step of 5 Apply Kirchhoff's Voltage Law at the node voltage in the circuit as shown in Figure 1. = v, Simplify further. 2 (1) Step of 5 Case (2): for Both the diodes and D2 are in reverse bias. Open the diodes and 2 as shown in Figure 1 and draw the equivalent circuit. + + - + v, 5V V + - 10 kΩ - Figure 2 There is no current flow in the circuit and the input will appear across the output (2) Step of 5 Case (3): for v, The diode D, is in reverse bias and the diode D2 is in forward bias. The diode D, acts as open and the diode D2 acts as short. Draw the equivalent circuit. + I + + v, 5V - - Figure 3 Step of 5 Apply Kirchhoff's Voltage Law at the node voltage as shown in Figure 4. = Simplify further. v,+5 2 = 2 +2.5 (3) Use equations (1), (2) and (3) to obtain the transfer characteristics. Therefore, the transfer characteristic of the circuit is, 2 1 =v, for for V