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Solutions to Problems 39 Comparing this with the equation for a straight line, we see that a plot of log k 1/T will have a slope of and an intercept equal to log A. Therefore, multiplying the slope of the line by -2.3R gives An example of such a plot is shown below. 13 12 Intercept = log A = 11 11 10 9 Slope = -2000 deg 8 7 :. = (2000 deg)(2.3)(1.98 cal deg⁻¹ log k = 9100 cal mol -1 = 9.1 kcal 6 At 400 K, log k = 6 5 At 300 K, 4 log k = 4.4 3 At 250 K, Experimental log k = 3 2 data At 200 K, log k = 1 0 0 0.001 0.002 0.003 0.004 0.005 1/T (deg⁻¹) 49. (a) We have a slight problem here: The positively polarized carbon atom in bromoethane has a closed shell and, therefore, is not a Lewis acid site. See Problem 51 for more on reactions of haloalkanes with Lewis bases. :0: H (b) CH₃CH₂ C + N H H H H H H (c) H + + CH₃ CH₂CH₃ :0: H :0: H (d) CH₃CH₂ C + H CH₃CH₂ H CH₃CH₂ H H H + (e) CH₃ + C H CH₃ H H H