GRE-Math-Questions-to-Know-by-Test-Day-2nd-Edition_pag233

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358. (B) You know the student is male (it’s given). The table (see the answer explanation 
to Question 357) shows there are 112 male students and that 38 of those 112 male students 
reside on campus. Thus, the probability that a randomly selected student resides on campus, 
given that the student selected is a male student = ≈38
112
0.34.
359. (E) The table (see the answer explanation to Question 357), there are 138 female 
students and 90 on-campus students. However, 52 of the 90 on-campus students are female 
students. Thus, the probability that a randomly selected student is female or resides on 
campus = + − = ≈138 90 52
250
0.704 0.70.
360. (B) If all the tagged turtles are still active in the lake when the second group of turtles 
is captured, the proportion of tagged turtles in the second group should equal the propor-
tion of tagged turtles in the whole population, P, of turtles in the lake. Set up a proportion 
and solve for P.
=
= =
P
P
6
30
20
(30)(20)
6
100 
361. (D) Discarding the highest number (7.1) and the lowest number (6.2) leaves 6.3, 6.4, 
and 6.5. The arithmetic average of these three numbers, by inspection, is 6.4.
362. (E) The highest reading (maximum value) is 15°F and the lowest reading (mini-
mum value) is −20°F. The range is the − ° − − ° =maximum value minimum value = 15 F ( 20 F)
° + ° = °15 F 20 F 35 F.
363. (B) The percent budgeted for rent is 40%. The percent budgeted for food and cloth-
ing combined is 17% + 17% = 34%. The difference is 40% − 34% = 6%. Thus, 6% of 
$3,500 = 0.06($3,500) = $210 is how much more money is budgeted for rent than for 
food and clothing combined. Tip: Rather than working with the percentages first, you can 
compute the money amounts first, and then subtract the amounts budgeted for food and 
clothing from the amount budgeted for rent to obtain the same answer.
364. (E) Store 1 sold 20 units of product A, 40 units of product B, 20 units of product C, 
and 30 units of product D, for a total of 110 units sold. Store 4 sold 20 units of product 
A, 30 units of product B, 20 units of product C, and 10 units of product D, for a total of 
80 units sold. The number of units sold by Store 1 is 110
80
(100%) = (1.375)(100%) = 
137.5% of the number of units sold by Store 4. Thus, the number of units sold by Store 1 
is 37.5% greater than the number of units sold by Store 4. 
365. (B) The average of the student’s unit exams is 
+ + =78 81 75
3
78. Therefore, the 
student’s numerical course grade is + +50%(78) 10%(92) 40%(75)
100%
 = 78.2.
07_McCune_Answer.indd 224 2/21/22 4:37 PM