Prévia do material em texto
SOLUTIONSMANUAL TO ACCOMPANY ATKINS' PHYSICAL CHEMISTRY 103 E4B.7(b) �e Clausius–Clapeyron equation [4B.9–133] is d ln p/dT = ∆vapH/RT2.�is equation is rearranged for ∆vapH, and the expression for ln p is di�erentiated. It does not matter that the pressure is given in units of Torr because only the slope of ln p is required. ∆vapH = RT2 d ln p dT = RT2 d dT (18.361 − 3036.8K T ) = RT2 (3036.8K T2 ) = (3036.8K)R = (3036.8K) × (8.3145 JK−1mol−1) = 25.249 kJmol−1 E4B.8(b) (i) �e Clausius–Clapeyron equation [4B.9–133] is d ln p/dT = ∆vapH/RT2. �is equation is rearranged for ∆vapH, and the expression for ln p is dif- ferentiated, noting from inside the front cover that ln x = (ln 10) log x. It does not matter that the pressure is given in units of Torr because only the slope of ln p is required. ∆vapH = RT2 d ln p dT = RT2 ln 10d log p dT = RT2 ln 10 d dT (8.750 − 1625K T ) = RT2 ln 10(1625K T2 ) = (1625K)R ln 10 = (1625K) × (8.3145 JK−1mol−1) × ln 10 = 31.11 kJmol−1 (ii) �e normal boiling point refers to the temperature at which the vapour pressure is 1 atm which is 760 Torr.�e given expression, log(p/Torr) = 8.750 − (1625K)/T is rearranged for T and a pressure of 760 Torr is substituted into it to give T = 1625K 8.750 − log(p/Torr) = 1625K 8.750 − log 760 = 276.9 K or 3.720 ○C Note that this temperature lies outside the range 15 ○C to 35 ○C for which the expression for log(p/Torr) is known to be valid, and is therefore an estimate. E4B.9(b) �e relationship betweenpressure and temperature along the solid–liquid bound- ary is given by [4B.7–132], p = p∗ + (∆fusH/T∗∆fusV)(T − T∗).�e value of ∆fusV is found using Vm = M/ρ where M is the molar mass and ρ is the mass density: ∆fusV = Vm(l) − Vm(s) = M ρ(l) − M ρ(s) = 46.1 gmol−1 0.789 × 106 gm−3 − 46.1 gmol−1 0.801 × 106 gm−3 = 8.75... × 10 −7m3mol−1 [4B.7–132] is then rearranged for T and the values substituted in to give T = T∗ + (p − p∗)T ∗∆fusV ∆fusH = ([−3.65 + 273.15]K) + ([100 × 106 − 1 × 105]Pa) × ([−3.65 + 273.15]K) × (8.75... × 10−7m3) 8.68 × 103 Jmol−1 = 272K or −0.935 ○C