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Step 9 7.014P Refer to Figure 7.6 in the text book. In order to get undistorted sine wave output from a BJT amplifier, BJT amplifier should operate in active region it will not enter into either cutoff or saturation region. For BJT amplifier circuit largest voltage gain is occurred when BJT operated near to saturation region. Output sine wave peak amplitude "P" and hence maximum allowed output negative swing without the transistor enters into saturation is "P" Maximum allowed output negative swing is added with gives the biased collector voltage of transistor without entering into saturation region from active region Point at which transistor should be biased is +P Step of 9 is the largest possible voltage gain Thus, Minimum supply voltage needed is Step (a) Determine the Minimum supply voltage when =-20 V/V and V: Substitute -20 V/V for 0.5 V for for and 0.2 V for P in the Thus, the minimum supply voltage is Step 9 (b) Determine the Minimum supply voltage when V/V and Substitute -50 V/V for A, 0.5 V for for and 0.2 V for P in the =2.25 V Thus, the minimum supply voltage is 2.25 V Step 9 (c) Determine the Minimum supply voltage when V/V and = Substitute -100 V/V for 0.5 V for for and 0.2 V for P in the equation. =3.5 V Thus, the minimum supply voltage is 3.5 V Step (d) Determine the Minimum supply voltage when =-100 V/V and Substitute -100 V/V for 0.5 V V for for and 1.0 V for P in the equation. V Thus, the minimum supply voltage is 4V Step (e) Determine the Minimum supply voltage when V/V and Substitute -200 V/V for A, 0.5 V V for for and 1.0 V for P in the equation. =5.6 V Thus, the minimum supply voltage is 5.6 V Step (f) Determine the Minimum supply voltage when = V/V and Substitute -500 V/V for 0.5 V for for and 1.0 V for P in the V =14V Thus, the minimum supply voltage is 14V Step 9 (g) Determine the Minimum supply voltage when =-500 V/V and V: Substitute -500 V/V for 0.5 for for and 2.0 V for P in the equation. =12.5 V+0.5 V+2 V Thus, the minimum supply voltage 15 V