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Step of 4 4.003P (a) Refer to Figure P4.3 (a) in the textbook. The diode is cut-off, and the diode is in the conducting mode in the circuit. The modified circuit diagram is, +1 V +2 V V I -3 V Figure 1 Step of 4 The voltage, V at the output terminal of Figure 1 is obtained as the voltage at the receiving end of the diode V V Therefore, the value of voltage V is 2V Calculate the value of the current that flows through the resistance. I = 2 kΩ V+5 = Substitute 2 V for V in the expression. 2+3 I = 5 = = 2.5 mA Therefore, the value of current I is 2.5 mA Step of 4 (b) Refer to Figure P4.3 (b) in the textbook. The diode is conducting, and the diode D2 is in the cut-off mode in the The modified circuit diagram is, +3 V I 2 +1 Vo V +2 V Figure 2 Step 4 of 4 The output voltage, V is obtained as the voltage at the receiving end at the diode, The voltage at the output terminal, V = 1 V Therefore, the value of voltage V is V Calculate the value of the current that flows through the resistance. 3-V I kΩ Substitute 1V for V in the expression. 3-1 I = 2 = mA Therefore, the value of current I is mA