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Step of 5 1.003P (a) Resistance R kΩ Current I is 5 mA According to ohms law V = IR V IR =5V Voltage V is According to power law P=VI P=VI = 0.025 W Power P is 0.025 W Step of 5 (b) Voltage V is 5V Current is mA According to ohms law V = IR A)R R R R=5kQ Resistance R is 5 According to power law P = VI P=VI A) = 0.005 W Power P is 0.005 W Step of 5 (c) Voltage V is 10 V Power P is 100 mW According to power law P = VI P=VI I (100x10⁻³ w) (10V) I mA Current I is 10 mA According to ohms law V = IR R V R=1kQ kΩ Resistance R is Step of 5 (d) Current is mA Power P is mW According to power law P = VI P=VI V=1V Voltage V is V According to ohms law V = IR V IR A)(R) 1V R= R=1kQ Resistance R is Step of 5 (e) Resistance R is Power P W Power P 1 A 1000 A Current I is 32 mA According to ohms law V = IR = =(32x10⁻³ 32 y Voltage V is 32