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Step of 6 8.026E Refer to Figure 7.34 (a) in the text book. Transfer ratio of the Wilson bipolar current mirror circuit is, = 100(100+1) = 1.000198 =0.9998 Step 2 of 6 Determine the percentage error in the transfer ratio. 1-0.9998 0.9998 0.0002 = 0.9998 (1) Thus, the transfer ratio of the Wilson circuit is 0.02% Step 3 of 6 Determine the transfer ratio of a simple current mirror circuit. = 1+ = 100 = 1+0.02 =0.98039 Step 4 of 6 Determine the percentage error in the transfer ratio. 1-0.98039 0.98039 (2) Thus, the percentage error in the transfer ratio is 2% Hence, from equations (1) and (2), the transfer ratio error is 0.02% for Wilson as opposed to 2% for the simple circuit. Step 5 of 6 Calculate the output resistance of a Wilson bipolar current mirror circuit. R. = 2 = = and = 2 = = 5 MΩ Thus, the output resistance of a Wilson bipolar current mirror circuit is 5 MΩ Step 6 of 6 Calculate the output resistance of a simple current mirror circuit. R. ro Ω = 100 Thus, the output resistance of a simple current mirror circuit is

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