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Step 1 of 4 8.008E Refer to Figure 7.4 (a) in the text book for the common-source amplifier circuit. Write the formula for transconductance 8ml of transistor Substitute for for and for = = = 1.25x10⁻³ A/V =1.25 mA/V Therefore, the transconductance 8ml of is Step 2 of 4 The resistance, is, Substitute V/m for , for L and for = 100 Ω = 18 kΩ Thus, the resistance is Step 3 of 4 The resistance, is, Substitute V/m for for L and for = 100 Ω Thus, the resistance is 21.6kQ . Step 4 of 4 The voltage gain is, Substitute 1.25x10⁻³ A/V for 8ml Ω for and Ω for = Thus, the voltage gain is -12.3 V/V