L4_Respostas

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1 = (320 it - = + F2 = + = 570N, = 320 = = 55,84°, F 570 = = 400 F 570 = (400) = 45,43°, cos = = - 250 = -250 570 ) = 116,01°, 570 2 F= - 270f+ intensidade + = (240)2 (680)21 = 770 N,, ws Ox = Fx = = 240 240 = 770 = F 770 = 770 270 = = 680 = (680) = 27,98°, 7703 = (3i - m ; r= - + r= - (4i - + + r= - - 4i + gi - + 15K r= + (6+5+ - + d= = + (26)2 = 31,51 m vetor = 31,51 - 26K) = 31,51 - 31,51 31,51 26 K directo = rx = 11 Ox= = 31,51 11 = d 31,51 = d = 31,51 = 31,51 -14 ) = 116,38°, = = 31,51 26 = 31,51 26 ) =4 (3m, 6m) = 2m, 1m) distance AB = = (5-3) + = m = rx2 + = (2) + = 8,83 vetor unitono U= = (2i- 5K) = 2 i - K 8,83 8,83 dAB 8,83 dire Ox = rx = 2 = 8,83 = 76,91°, 8,83 -7 cos dAB = 8,83 Oy = = 142, = = -5 8,83 = = 124,5 (0,80,0) 2 40m 80m FAB AB A = (40,0,-30) AB= = VAB= dxi + 1 + (30m) K 23 + d= = + = 94,34 m dx vetor unitario dz u= rAB = -40 i + + d 94,34 componentes do = u = F. = F 94,34 -1 F= = 94,34 + 80 + 2500.30 k 94,34 94,34 I 2500. 94,34 :- = 2500.80 94,34 = 2500.30 94,34 = 795N] = Fx = Ox = 2500 = 115, F 2500 Fy = 2120 F 2500 = 2500 2120 ) = = = 795 F 2500 = ) = 71,6 Ox= 70,9° 144,90 ; - 230 N Oz7 A (0,30,0) = 2335 N N 30m BA BA= TAB : dxi dyd -1 dak FAB = + - 7,5 } B d= = + + d= = (6) 2 + + = 31,5 m d dz unitario de TAB = - d 31,5 Componentes da force + 31,5 - 2335. 6 i + 2335.30 - K 31,5 31,5 31,5 I = 2335. 6 = 76 31,5 II fy= = 2335.30 = 31,5 III - = 31,58 A A A= = m A FA (-0,5,0,0) = (0, - 2,299, 0,75) m B 1 1m (0,0,0) = FA= 300N 250N -2,299, m vetor rAB = B-A = + - = + + = + = 2,418 m # unitário u1= ΓAB = - 0,75 dAB vetor = (-0,5- (-2,5) + = - 0,75 K = + + = = 3,138 m # vetor unitario = dcD 3,138 Representação FA = = = 2,418 - 2,418 2,418 [FA = - = 3,138 = 3,138 3,138 250.0,75 3,138 K = 150, -9 Posicoes FB FA 4m A (0,0, 4) m 2m 4m 4+1,5) m D c I 3m Y (-1, 4, 250N D = (2, -3, 0) = 175N vetor posicio rBD= (2-0)i + = dBD + = (-2)2 + (5,5)2 = 6,576 m # vetor unitario = = dBD 6,576 vetor posição = C-A = + + (0-4) = -1i+ 4K = + = = 5,744 m # vetor unitario = - dAc 5,744 FA = FA. = 250. 5,744 5,744 + 250.4 5,744 - 250.4 5,744 K FA = 43,52i + - = FB. = = 175.2 175.3 - 175.5,5 6,576 6,576 = 53,22i - 79,831210 10 D E Posicão F B= (480, 0, 600) mm 0 400 D= = (0, 280) mm vetor 480 1712 N B-D = (480 - 1 + rBD = 480i - + dBD = = + dBD = 770 mm #vetor = rBD = - + dBD 770 da UBD = 770 - 1712. 770 480 - 1712.510 + 1712.320 770 770 + 711,48k Fx= = 1067,22 N// = 711,48