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Solutions to Problems 173 + H + (f) H + CH₃ CH₃ CH₃ C(CH₃)₃ + CH₃ C(CH₃)₂ + (g) CH₃ CH₃ CH₃ + CH₃ CH₃ + (h) CH₃ CH₃ CH₃ + CH₃ CH₃ CH₃ CH₃ CH₃ CH₃ CH₃ CH₃ CH₃ + also CH₃ CH₃ CH₃ H CH₃ + CH₃ CH₃ CH₃ CH₃ CH₃ + CH₃ 32. These conditions favor rearrangements. They allow carbocations to exist for a long time, because the reaction mixtures are strongly acidic and lack decent nucleophiles. (a), (b) CH₃CH=CH₂ (c) (major product) (d) (CH₃)₂C=CH₂ (e) (CH₃)₃CCH=CH₂, (CH₃)₂C=C(CH₃)₂ (major product), CH(CH₃)₂ H₂C=C CH₃ Line formulas will be used for most of the cyclic structures below. Note that methyl groups are understood to be present at the ends of lines even when "CH₃" is not written in. (f) (major product) CH₃ CH₃ CH₃ CH₂ C(CH₃)₃ CH₃ CH₂ CH₃ (g)