1 (160)

Prévia do material em texto

Step 10 4.056E Consider the following function Wr the truth table as shown in Table 1: Table XYZF 0001 001 1 0 0 1 0110 1000 0 1 0 0 1110 Step 10 Draw the Karnaugh Map as shown Figure 1: YZ YZ YZ YZ X 1 1 0 1 / 0 0 0 X 0 XY XZ Figure 1 Step 3 of 10 From Figure F= group1 (pink color line) group2 (blue color line) F=XY+XZ Therefore, the final Boolean expression F=X(Y+Z) Step 10 Consider the following function. the truth table shown Table 2: Table XYZG 0001 0 0 0 0100 0110 1001 1010 1 1 1110 Step 10 Draw the Karnaugh Map as shown 2 YZ YZ YZ YZ X 0 0 0 1 X 1 0 0 1 XZ YZ Step 10 Figure 2 Step 10 From G= group1 (pink color group2 (blue color line) G=XZ+YZ Therefore, the final Boolean expression G=Z(X+Y) Step 10 Consider the following H= Write the truth table as shown in Table 3: XYZH 0 0 0011 0101 0110 1001 1 0 0 1101 1110 Step 10 Draw the Karnaugh Map as Figure YZ YZ YZ YZ X 1 1 0 1 X 1 \ 0 0 1 XY Z Figure Step 10 From Figure 3, Write the Boolean expression as H= group1 (blue color group2 (pink color line) H=XY+Z Therefore, the final Boolean expression H=XY+Z