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Chapter 11: Bonding II: Additional Aspects 498 1 2 1 2 1 4 1 3 2spc h FHG I KJ L NM O QP / sin cos In the xy-plane = 90 so that the function becomes (sin(90 ) = 1) 1 2 1 2 1 4 1 3 2spc h FHG I KJ L NM O QP / cos We now evaluate the functional form of one of the other sp2 hybrids. Y pyd i FHG I KJ 3 4 1 2/ sin sin 2 2 1 3 2 1 6 2 1 2 2sp s p px yc h b g b g d i 2 2 1 2 1 2 1 2 1 3 1 4 1 6 3 4 1 2 3 4 spc h FHG I KJ F HG I KJ F HG I KJ / / / sin cos sin sin 2 2 1 2 1 4 1 3 1 6 3 1 2 3spc h FHG I KJ L NM O QP / sin cos sin sin 2 2 1 2 1 4 1 3 1 2 3 2 spc h FHG I KJ L NM O QP / sin cos sin sin Again in the xy plane we have 2 2 1 2 1 4 1 3 1 2 3 2 spc h FHG I KJ L NM O QP / cos sin The third sp2 hybrid is 1/ 2 2 3 1 1 1 3 sin cos sin sin 4 3 2 2 sp and in the xy plane 1/ 2 2 3 1 1 1 3 cos sin 4 3 2 2 sp